※ 引述《wgs (我需要超级机械可鲁)》之铭言： : 请问各位神人 : CH3 : ∣ CH3OH : CH3C——CH2 -----------------> ? : ＼╱ ∣ H﹢ ---------------- : O ∣ : ∣ : ∣ CH3ONa : ∣----------------> ? : CH3OH ---------------- : 请问这两者不同的酸是如何开环加成的 : 我有考虑到二级碳一级碳的问题 可是想不出所以然 : 有高手知道吗 As treating this epoxide with proton in MeOH, protonation occurs to generate the epoxide-proton cation, which could be regard as the equivalent of alpha-hydroxy tertiary carbon cation... thus the methanol addition takes place on the tertiary carbon to form the alpha-hydroxyl ether. but to deal the epoxide with sodium methoxide, no elimination will happen because non of the protons of epoxide would be trapped by methoxide anion. Based on this, no reaction will undergo but nucleophilic attack. the less steric hindered carbon attacked by methoxide resulted in ring opening to form another kind of alpha-hydroxyl ether. -- 在人的一生当中，谁没有一些...醒不了的梦；挥不去的痛． 我想，只要待人以诚，爱人以真，从来没有刻意去伤害谁． 只希望能做到............不负人，不负我！ --

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