网址: https://stackoverflow.com/questions/49890211/address-operator-and-array-in-assembly-level 在Answer里面提到: The address of & operator allows you to construct a pointer to value from a variable of same type as value. 中文翻译:address operator允许你建构一个指标(from一个变数to value，且这个变数有 跟value一样的type) 请问，这一行的意思是不是指，当执行程式这一行时: p = &var1; &本身也会占用一个variable的空间(用来放var1的address)，然後在把这个address给p? 接下来，内文提到: int *p = &A; 程式在做这行指令时，you are doing an assignment from a pointer to array of int into a variable of type array of int, which is a different type. 光看这行英文，哪有different type，一样是array of int啊 还是他打错了?应该是from a pointer to int into a variable of type array of int? 谢谢。 --

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