作者hsien0701 ( 兴大研究生-贤)
看板C_and_CPP
标题[问题] 将动态记忆体里的值输出成一.txt
时间Thu Oct 22 19:23:07 2009
各位大大..抱歉打扰了
我把4个fin00%d.txt档的资料链结串列起来成ㄧ个out.txt
可是输出都是只输出最後一个.txt里头的资讯
以下是我的程式码
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <memory.h>
#define size 160
void Read (char file_name[40]);
void write ();
void append();
int Data_num;
struct node
{
unsigned char buffer_1D[size];
struct node *next;
};
typedef struct node Node;
Node *first, *current;
unsigned char *output;
unsigned char buffer[4*size]={0};
int main(void)
{
int i=0,j=0,n=0;
output = (unsigned char *)malloc(sizeof(void*));
char InName[40] ="fin000.txt";
for(Data_num=1;Data_num<=4; Data_num++)
{
sprintf(InName,"fin00%d.txt",Data_num);
first = (Node*)malloc(sizeof(Node*));
Read (InName);
first->next=NULL;
current=first;
printf(" %d\n",current->buffer_1D[n]);
system("pause");
append();
while(first!=NULL)
{
first=first->next;
}
write();
}
return 0;
}
void append()
{
Node *previous;
previous=(Node*)malloc(sizeof(Node*));
current->next=previous;
previous->next=NULL;
current=previous;
}
void Read ( char file_name[40])
{
int i=0,j=0,n=0;
unsigned char in0;
FILE *fp_input;
fp_input = fopen(file_name,"rb");
if(fp_input == NULL)
{
printf( "\n Can't open file %s",file_name);
system("pause");
exit(0);
}
n=0;
while ((fscanf(fp_input, "%d\n",&in0))!=EOF)// && first!=NULL)
{
first->buffer_1D[n]=in0;
buffer[n]=in0;
n++;
//printf("%d %d %d\n",n,first->buffer_1D[n] ,in0);
//system("pause");
if(n>size)
{
break;
}
}
fclose(fp_input);
}
void write()
{
FILE *fp_output;
int i=0,j=0,n=0;
fp_output =fopen("out.txt","wb");
if (fp_output == NULL)
{
printf("\n Can't open file \n");
}
else
{
for(n=0; n<size ; n++)//这里是只会输出最後ㄧ个.txt里头资讯的原因
{
*output=buffer[n];
fprintf(fp_output," %d \n",*output);
}
}
fclose(fp_output);
}
可否指点一下怎嚜把四个.txt的资讯循序输入经串列一起输出成ㄧ个.txt档
因为我不知道怎嚜观看动态记忆体里头的资讯
所以可否请各位教学一下..拜托拜托!!
--
※ 发信站: 批踢踢实业坊(ptt.cc)
◆ From: 114.43.9.248
1F：→ j00249:malloc(sizeof(Node*)) 应该改成 Node 吧 10/22 23:48
2F：推 ranshell:fopen(xxx, "wb+"); 才是append 10/23 09:32