作者tga123 (叛帝)
看板AndroidDev
标题[问题] 让Fragment共用httpclient
时间Wed Dec 5 10:57:55 2012
我有写一段httprespones的方法
在我按下按钮会建立Fragment.
同时也会执行 HTTPRESPONSE程序
当我按下返回按钮 HTTPRESPONSE程序并没有中止动作.
重复执行几次之後会造成我的伺服器当机.
我现在有两个想法:
1.当我按下返回按钮的时候会立即终止HTTPRESPONSE程序的动作应该就不会造成当机.
2.共用httpResponse在Activity就不会产生新的HTTPRESPONSE程序.
3.httpResponse的方法中有终止的方法??????
希望版友能给些帮助
感激不尽
下面是我的程式码:
Handler mHandler = new Handler()
{
@Override
public void handleMessage(Message msg )
{
switch (msg.what)
{
case REFRESH_DATA:
String result = null;
if (msg.obj instanceof String)
result = (String) msg.obj;
if (result != null)
Toast.makeText(templistview.this.getActivity(), result,
Toast.LENGTH_LONG).show();
break;
}
}
};
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState) {
super.onCreateView(inflater, container, savedInstanceState);
View view = inflater.inflate(R.layout.templistmune, container,
false);
Thread b = new Thread(new sendPostRunnable(msg));
b.start();
return view;
}
private String sendPostDataToInternet(String strTxt)
{
HttpPost httpRequest = new HttpPost(uriAPI);
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair(M1,M2));
params.add(new BasicNameValuePair(M3,M4));
params.add(new BasicNameValuePair(M5,M6));
try
{
httpRequest.setEntity(new UrlEncodedFormEntity(params, HTTP.UTF_8));
httpResponse = new DefaultHttpClient().execute(httpRequest);
if (httpResponse.getStatusLine().getStatusCode() == 200)
{
String strResult = EntityUtils.toString(httpResponse.getEntity());
return strResult;
}
} catch (Exception e)
{
e.printStackTrace();
}
return null;
}
class sendPostRunnable implements Runnable
{
String strTxt = null;
public sendPostRunnable(String strTxt)
{
this.strTxt = strTxt;
}
@Override
public void run()
{
String result = sendPostDataToInternet(strTxt);
mHandler.obtainMessage(REFRESH_DATA, result).sendToTarget();
}
}
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◆ From: 119.14.80.132
1F:→ KeySabre:把该thread停掉 12/05 13:33
2F:→ tga123:停掉这条程序就可以了吗xxd这麽简单 12/05 14:47