作者oklp1415 (天生我材)
看板Ajax
标题[问题] JS上使用Click没有反应
时间Sun Jan 3 09:55:35 2016
我要做的事情是，当我按下Button按钮，会自动执行JSON内的资料内容，并把宣告的
JSON资料填入到Table中，但是我卡关的地方，按下Click後都没有反应
不知道是我哪里理解有错误，希望有人可以指导一下!!感谢，附上我撰写的Code
<fieldset>
<form>
<input type="button" value="显示名称"
onclick="getTemp(
#temp_div)" />
</form>
<table>
<div id="temp_div"></div>
<tr>
<th>User_Name</th>
<th>score</th>
<th>team</th>
</tr>
</div>
</table>
</fieldset>
<script type="text/javascript" src="js/jquery-1.8.3.min.js"></script>
<script type="text/javascript">
$(document).ready(function () {
var json = [
{"User_Name":"1","score":"100","team":"1"},
{"User_Name":"2","score":"80","team":"2"},
{"User_Name":"3","score":"90","team":"2"}
{"User_Name":"4","score":"33","team":"2"}
{"User_Name":"5","score":"38","team":"2"}
{"User_Name":"6","score":"64","team":"2"}
];
var tr;
for (var i = 0; i < json.length; i++) {
tr = $('<tr/>');
tr.append("<td>" + json[i].User_Name + "</td>");
tr.append("<td>" + json[i].score + "</td>");
tr.append("<td>" + json[i].team + "</td>");
$('table').append(tr);
}
});
</script>
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※ 编辑: oklp1415 (122.121.191.85), 01/03/2016 09:57:05
1F：→ f7811202002: 你的getTemp function? 01/03 15:14