作者JYHuang (夏天到了，冷不起来了说)
看板Ajax
标题[JQuery] 选取children的children
时间Tue Jan 6 22:48:58 2009
== HTML ==
<td rel="
dropdown_menu"> TEXT <
a id="login" href="javascript:void(0)">
<
img src="default.png" align="top"> <
/a>
</td>
<td rel="
dropdown_menu"> TEXT1 <
a id="search" href="javascript:void(0)">
<
img src="default.png" align="top"> <
/a>
</td>
== JQuery ==
$("td[@rel='
dropdown_menu']").hover(
function(){
$(this).children("
A > IMG").attr("src","hover.png");
},
function(){ ......
}
)
为何用.children("
A>
IMG")或是.children("
A IMG")都无效？
要用到$(this).children("
A").children("
IMG")才能选择
--
※ 发信站: 批踢踢实业坊(ptt.cc)
◆ From: 59.104.154.32