作者sky2fly (())
看板ASM
标题[问题] 有人可以帮我看一下吗??
时间Thu Jul 26 20:33:39 2007
Part II:
00401308 |> 0FBE08 /MOVSX ECX,BYTE PTR DS:[EAX]
0040130B |. 03C9 |ADD ECX,ECX
0040130D |. 50 |PUSH EAX
0040130E |. 8D14C9 |LEA EDX,DWORD PTR DS:[ECX+ECX*8]
00401311 |. 03EA |ADD EBP,EDX
00401313 |. FFD7 |CALL EDI
00401315 |. 8038 00 |CMP BYTE PTR DS:[EAX],0
00401318 |.^75 EE \JNZ SHORT (censored).00401308
Try to understand what part II does. ADD ECX,ECX means ECX gets doubled.
For username “azerton”, part II is 3CA6 (15526.)
请问高手这3CA6的十六位元码 是如何得到的呢 感激阿
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1F：→ zha0:上面的程式码好像没 3CA6 吧 ^^|| 07/27 22:15